4cos^2x+2sin^2x=3

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Solution for 4cos^2x+2sin^2x=3 equation: 


Simplifying
4cos2x + 2sin2x = 3

Solving
4cos2x + 2in2sx = 3

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2in2sx' to each side of the equation.
4cos2x + 2in2sx + -2in2sx = 3 + -2in2sx

Combine like terms: 2in2sx + -2in2sx = 0
4cos2x + 0 = 3 + -2in2sx
4cos2x = 3 + -2in2sx

Divide each side by '4os2x'.
c = 0.75o-1s-2x-1 + -0.5in2o-1s-1

Simplifying
c = 0.75o-1s-2x-1 + -0.5in2o-1s-1

Reorder the terms:
c = -0.5in2o-1s-1 + 0.75o-1s-2x-1

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